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1=96(3/4)^x
We move all terms to the left:
1-(96(3/4)^x)=0
Domain of the equation: 4)^x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(96(+3/4)^x)+1=0
We multiply all the terms by the denominator
-(96(+3+1*4)^x)=0
We calculate terms in parentheses: -(96(+3+1*4)^x), so:x=0/1
96(+3+1*4)^x
We add all the numbers together, and all the variables
967^x
Back to the equation:
-(967^x)
x=0
Równanie nie ma rozwiązania
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